(27x^2+64)/(3x+4)

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Solution for (27x^2+64)/(3x+4) equation: 


D( x )

3*x+4 = 0

3*x+4 = 0

3*x+4 = 0

3*x+4 = 0 // - 4

3*x = -4 // : 3

x = -4/3

x in (-oo:-4/3) U (-4/3:+oo)

(27*x^2+64)/(3*x+4) = 0

27*x^2 = -64 // : 27

x^2 = -64/27

x belongs to the empty set

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